Two resistances are measured in ohm and are given as: R 1 = 3 Ω ± 1 % R 2 = 6 Ω ± 2 % When they are connected in parallel, the percentage error in equivalent resistance is

Step-by-step solution

1 R e q = 1 R 1 + 1 R 2 d R e q R 2 = d R 1 R 1 2 + d R 2 R 2 2 ⇒ d R e q R e q = d R 1 R 1 2 + d R 2 R 2 2 × R e q ⇒ 1 3 + 2 6 × 2 ⇒ ∴     % error = 4 3 %