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A ray of light of intensity I is incident on a parallel glass-slab at the point A and it undergoes partial reflection and refraction as shown in the figure. At each reflection, 25 %   of the incident energy is reflected and the rest is transmitted. If the rays A B and A ′ B ′   undergo interference, then the ratio I max I min is

Options

  1. A4 : 1
  2. B8 : 1
  3. C7 : 1
  4. D49 : 1

Correct answer

D. 49 : 1

Step-by-step solution

From figure I 1 = I 4 and I 2 = 9 I 64 ⇒ I 2 I 1 = 9 16 By using I m a x I m i n = I ⁡ 2 I ⁡ 1 + 1 I ⁡ 2 I ⁡ 1 - 1 2 = 9 1 6 + 1 9 1 6 - 1 2 = 4 9 1

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