NTA Abhyas JEE Main2020PhysicsWave OpticsPractice
Two beams of light having intensities I and 4 I , interfere to produce a fringe pattern on a screen. The phase difference between the beams is π 2 , at a point A and π , at a point B . The difference between the resultant intensities at A and B is
Options
- A2 I
- B4 I
- C5 I
- D7 I
Correct answer
B. 4 I
Step-by-step solution
Resultant intensity due to superposition of two waves on the screen is given as I ϕ = I 1 + I 2 + 2 I 1 I 2 cos ϕ Here, I 1 = I and I 2 = 4 I At point A, ϕ = π 2 ∴ I A = I + 4 I = 5 I At point B, ϕ = π ∴ I B = I + 4 I - 4 I = I ∴ I A - I B = 4 I