Two beams of light having intensities& I and& 4I , interfere to produce a fringe pattern on a screen. The phase difference between the beams is (π)/(2) , at a point& A and π , at a point B . The difference between the

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Correct answer: B. 4I

Resultant intensity due to superposition of two waves on the screen is given as

\text{I} \left(ϕ\right) = {I}_{1} + {I}_{2} + 2 \sqrt{{I}_{1} {I}_{2}} \text\cos ϕ

Here, &

{I}_{1} = {I and I}_{2} = 4 \text{I}

At point A,

ϕ = \dfrac{\pi}{2} ∴ {I}_{A} = \text{I} + 4 \text{I} = 5 \text{I}

At point B,

ϕ = \pi ∴ {I}_{B} = \text{I} + 4 \text{I} - 4 \text{I} = \text{I}

∴ {I}_{A} - {I}_{B} = 4 \text{I}

Two beams of light having intensities& I and& 4I , interfere to...

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