NTA Abhyas JEE Main2020PhysicsWave OpticsPractice
In Young's double-slit experiment, the distance between slits and the screen is 1 m and monochromatic light of wavelength 600 nm is being used. A person standing near the slits is looking at the fringe pattern. When the separation between the slits is varied, the interference pattern disappears for a particular distance d 0 between the slits. If the angular resolution of the eye is 1 60 ° , then the value of d 0 is c
Options
- A1   mm
- B3   mm
- C2 mm
- D4   mm
Correct answer
C. 2 mm
Step-by-step solution
When the angular fringe width in the interference pattern becomes less than the angular resolving power of the person's eye, the fringes will disappear. The angular fringe width θ 0 = β D = λ d 0 d 0 = λ θ 0 = 600 × 10 − 9 ( 1 60 × π 180 ) d 0 = 600 × 60 × 180 × 10 − 9 π   m = 2   mm