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In Young's double-slit experiment intensity at a point is (3/4) th of the maximum intensity. The possible angular position of this point is

Options

  1. Asin -1 λ 3d
  2. Bsin -1 λ 2d
  3. Csin -1 λ 6d
  4. Dsin -1 λ 4d

Correct answer

C. sin -1 λ 6d

Step-by-step solution

I = I max cos 2 ϕ 2  ∴    3I max 4 = I max  cos  2 ϕ 2 cos ϕ 2 = 3 2 or, ϕ 2 = π 6  ∴     ϕ = π 3 = 2 π λ Δ x                      .....(i)  where, Δ x = d sin θ Substituting in Eq.(i) we get sin θ = λ 6d or, θ = sin -1 λ 6d  

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