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First diffraction minimum due to a single slit of width 10 - 4 c m is at θ = 30 o . The wavelength of the light used is

Options

  1. A4000 Å
  2. B5000 Å
  3. C6000 Å
  4. D6250 Å

Correct answer

B. 5000 Å

Step-by-step solution

a sin ⁡ θ = 1 × λ ⇒ λ = a sin ⁡ θ = 10 - 4 × 1 2 = 10 × 10 - 5 2 = 5 × 10 - 5 c m = 5000 Å

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