In Young’s double-slit experiment, the two slits, 0 . 12 mm apart, are illuminated by monochromatic light of wavelength 420 nm . If the screen is 1 . 0 m away from the slits, then the distance of the second bright fringe from the central maximum is

Step-by-step solution

Here d = 0.12 mm = 0.12 × 10 − 3 m = 12 × 10 − 5 m λ = 420 nm = 420 × 10 − 9 m , D = 1.0 m The distance of the second bright fringe x 2 = 2 λ D d                                                                                   &#8