NTA Abhyas JEE Main2020PhysicsWave OpticsPractice
In the YDSE shown below, two slits are covered with thin sheets having a thickness t and 2 t and refractive indices 2 μ and μ respectively. The position of central maxima is shifted by a distance of N (in cm ) from the central position of the screen. Find the value of N . [ d = 1 mm ; D = 1 m ; t = 2 × 10 - 2 mm , μ = 3 2 ]
Correct answer
2
Step-by-step solution
d   sin θ   =   ( 2 μ t   +   t )   –   2 μ t ⇒ d y D = t ⇒ y = D t d ⇒ y = 1 × 2 × 1 0 - 5 1 × 1 0 - 3 = 2 × 1 0 - 2  m