Consider single slit experiment of diffraction of light. If the light of wavelength 5000 A ∘ fall on a slit of width 1 μ m then the angular width of central maximum is

Step-by-step solution

d sin ⁡ θ = λ   sin ⁡ θ = λ d   For first minima = 5   ×   10 - 7 10 - 6 sin ⁡ θ = 5 10 θ = 30 ° Angular width of first minima 2 θ = 60 °