NTA Abhyas JEE Main2020PhysicsWave OpticsPractice
Light of wavelength 600 n m is incident normally on a slit of width 0.2 m m . The angular width of the central maxima in the diffraction pattern is n × 10 - 3 rad , then what is the value of n ? (measured from minimum to minimum)
Correct answer
6
Step-by-step solution
λ = 600 n m = 600 × 1 0 - 9 m d = 0.2 m m = 0.2 × 1 0 - 3 m ∵ Linear width of central maximum, x = 2 θ D Where, 2 θ : Angular width of central maximum. We know that, x = 2 λ D d Angular width 2 θ . D = 2 λ D d ⇒ 2 θ = 2 λ d = 2 × 600 × 1 0 - 9 0.2 × 1 0 - 3 = 6 × 1 0 - 7 × 1 0 4 = 6 × 1 0 - 3 r a d