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Fraunhofer diffraction pattern of a single slit is obtained in the focal plane of the lens of focal length 1 m . If the third minimum is formed at a distance of 5 mm from the central maximum and wavelength of light used is 5000 A ∘ , then the width of the slit will be

Options

  1. A0 . 02   cm
  2. B0 . 03 cm
  3. C0 . 04 cm
  4. D1 cm

Correct answer

B. 0 . 03 cm

Step-by-step solution

Using a sin ⁡ θ = n λ Or a . x f = 3 λ or a = 3 λ . f x = 3 × 500 × 10 - 9 × 1 5 × 10 - 3 = 3 × 10 - 4 m = 0.03 c m

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