NTA Abhyas JEE Main2020PhysicsWaves and SoundPractice
The respective displacements (in cm ) of two particles of a medium disturbed by a wave propagation at x 1 = 0 and x 2 = 1   cm are given by the equations: y 1 = 2   sin   3 πt y 2 = 2   sin   ( 3 π t - π / 8 ) The speed of the wave is
Options
- A16   cm   s - 1
- B24   cm   s - 1
- C12   cm   s - 1
- D8   cm   s - 1
Correct answer
B. 24   cm   s - 1
Step-by-step solution
Given ω=3π ∴ f= ω 2π =1.5 Also Δx=1.0 cm Given ϕ = 2π λ Δx ⇒ π 8 = 2π λ ×1 ⇒ λ=16 cm ⇒ v=fλ=16×1.5=24 cm sec - 1