The ends of a stretched wire of length l are fixed at x = 0 and x = l . In one experiment, the displacement of the wire is y 1 = a sin ⁡ π x l sin ⁡ ω t and energy E 1 and in another experiment, its displacement is y 2 = a sin ⁡ 3 π x l sin

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The ends of a stretched wire of length l are fixed at x = 0 and x = l . In one experiment, the displacement of the wire is y 1 = a sin ⁡ π x l sin ⁡ ω t and energy E 1 and in another experiment, its displacement is y 2 = a sin ⁡ 3 π x l sin ⁡ 3 ω t and energy is E 2 then

Quantrex Academy · Accepted Answer

Correct answer: D. E 2 = 9 E 1

In first case freq. ⇒ ω 1 = ω In second case freq. ω 2 = 3 ω ∵ E n e r g y α f r e q . 2 E 1 E 2 = ω 2 ( 3 ω ) 2 ⇒ E 2 = 9 E 1

The ends of a stretched wire of length l are fixed at x = 0 and x = l . In one experiment, the displacement of the wire is y 1 = a sin ⁡ π x l sin ⁡ ω t and energy E 1 and in another experiment, its displacement is y 2 = a sin ⁡ 3 π x l sin ⁡ 3 ω t and energy is E 2 then

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