NTA Abhyas JEE Main2020PhysicsWaves and SoundPractice
The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is 0.5 π . The wave velocity is
Options
- A144 m s - 1
- B384 m s - 1
- C256 m s - 1
- D720 m s - 1
Correct answer
B. 384 m s - 1
Step-by-step solution
Here, f = 120 Hz , x = 0.8 m and ϕ = 0.5 π . From, ϕ = 2 π λ x and λ = 2 πx ϕ = 2 π × 0.8 0.5 π = 3.2 m v = nλ = 120 × 3.2 = 384 m s - 1