NTA Abhyas JEE Main2020PhysicsWaves and SoundPractice
The displacement y of a particle in a medium can be expressed as y = 10 - 6 sin 100 t - 20x + π / 4 m , where t is in seconds and x in meters. The speed of the wave is
Options
- A2000   m   s - 1
- B5   m   s - 1
- C20   m   s - 1
- D5 π   m   s - 1
Correct answer
B. 5   m   s - 1
Step-by-step solution
Given wave equation : y = 10 - 6 sin 100 t + 20x + π 4   m Standard equation : y = a sin  ωt + k x + ϕ Comparing the two, we obtain ∴   ω = 100 and k = 20 ∴ ω k = 100 20 ⇒ 2 πn 2 π / λ = nλ = v = 5 ∴ v = 5   m   s - 1