NTA Abhyas JEE Main2020PhysicsWaves and SoundPractice
Two points on a travelling wave, having frequency 500 Hz and velocity 300 m s - 1 , are 60 ° out of phase. The minimum distance between the two points is
Options
- A0.2
- B0.1
- C0.5
- D0.4
Correct answer
B. 0.1
Step-by-step solution
v = n λ ∴         λ = v n = 300 500 = 3 5   m Now, phase difference = 2 π λ × path difference ∴       π 3 = 2 π λ × path difference   o r       π 3 = 2 π × 5 3 × path difference path difference = 3 × 60 × π 2 π × 5 × 180 = 0.1   m