NTA Abhyas JEE Main2020PhysicsWaves and SoundPractice
A uniform rope of mass 6 kg and length 6 m hangs vertically from a rigid support. A block of mass 2 kg is attached to the free end of the rope. A transverse pulse of wavelength 0 . 075 m is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is K cm where K is
Correct answer
15
Step-by-step solution
T 1 = 2 × 10 = 20 N T 2 = ( 2 + 6 ) 10 = 80 N V 2 V 1 = 80 20 = 2 Frequency remains unchanged So λ 2 λ 1 = 2 λ 2 = 2 × 0.075 = 0 . 15 m K = 15 c m