NTA Abhyas JEE Main2020PhysicsWaves and SoundPractice
Frequency of the em signal emitted by a rocket is 4 × 10 7 H z . If apparent frequency observed on earth is 3.2 × 10 7 H z , then velocity with which rocket is moving away is [speed of light = c ]
Options
- A0 . 5   c
- B0 .7 c
- C0 .9 c
- D0 . 2 c
Correct answer
D. 0 . 2 c
Step-by-step solution
We know that υ = υ 0 c - v c + v or v = ∆ υ υ 0 × c v = 0.8 × 10 7 4 × 10 7 × 3 × 10 8 = 6 × 10 7   m   s - 1 = 0.2   c