NTA Abhyas JEE Main2020PhysicsWaves and SoundPractice
The wavelengths of two notes in the air are 36 195 m and 36 193 m . each note produces 10 beats per second separately with a third note of fixed frequency. The velocity of sound in air in m s - 1 is
Options
- A330
- B340
- C350
- D360
Correct answer
D. 360
Step-by-step solution
Beat frequency= v 1 ~ v 2 Let the frequency of third note be n . Then, 195 v 36 - n = 10     … i And n - 193 v 36 = 10   … i i Adding Eqs. (i) and (ii) v 18 = 20 ⟹     v = 360   m   s - 1