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NTA Abhyas JEE Main2020PhysicsWaves and SoundPractice

A pipe closed at one end has length 83 cm . The number of possible natural oscillations of air column whose frequencies lie below 1000 Hz are (velocity of sound in air = 332 m s - 1 )

Options

  1. A3
  2. B4
  3. C5
  4. D6

Correct answer

C. 5

Step-by-step solution

Fundamental frequency n = V 4 L = 332 4 × 83 × 10 − 2 = 100 . Hence possible frequencies are n = 100 . n 1 = 300 . n 2 = 500 . n 3 = 700. n 5 = 900 .

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