NTA Abhyas JEE Main2020PhysicsWaves and SoundPractice
The equation of a wave on a string of linear mass density 0 . 04 kg m - 1 is given by y = 0.02 m sin 2 π t 0.04 ( s ) - x 0.50 ( m ) The tension in the string (in N ) is:
Correct answer
6.25
Step-by-step solution
From the given equation v = λ T = 0.50 0.04 Now v = T μ ⇒ T = v 2 μ = 12.5 2 × 0.04 = 6.25 N