NTA Abhyas JEE Main2020PhysicsWaves and SoundPractice
A string fixed at both ends has a standing wave mode for which the distances between adjacent nodes is 18 cm. For the net consecutive standing wave mode distance between adjacent nodes is 16 cm. The minimum possible length of the string is
Options
- A144     cm
- B204     cm
- C288     cm
- D72     cm
Correct answer
A. 144     cm
Step-by-step solution
Let the vibration takes place in the nth mode So, for 1 s t case, n λ 2 = L ......(i) And for 2 n d case, n + 1 λ ′ 2 = L .....(ii) From Equations. (i) and (ii), we get n λ 2 = ( n + 1 ) λ ′ 2 ∵ λ 2 = 18 cm a n d λ ′ 2 = 16 cm ⇒ 18 n = n + 1 16 ⇒ n = 8 So, minimum possible length l = n λ 2 ⇒ l = 8 × 18 = 144 cm