NTA Abhyas NEET2020ChemistryChemical KineticsPractice
The inactivation of a viral preparation in a chemical bath is found to be a first order reaction. The rate constant for the viral inactivation if in the beginning 1.5 % of the virus is inactivated per minute is ( Given : ln 100 98.5 = 0.01511 )
Options
- A1.25 × 10 - 4 s e c - 1
- B2.5 × 10 - 4 s e c - 1
- C5 × 10 - 4 s e c - 1
- D2.5 × 10 - 4 m i n - 1
Correct answer
B. 2.5 × 10 - 4 s e c - 1
Step-by-step solution
The rate constant for the viral inactivation k = 1 60 ln 100 100 - 1.5 k = ( 0.015 ) 60 k = 2.5 × 10 - 4 s e c - 1