For a given reaction, energy of activation for forward reaction E a f is 80 kJ mol -1 and Δ H = - 40 kJ mol -1 . A catalyst lowers E a f to 20 kJ mol − 1 . The ratio of energy of activation for reverse reaction before and after addition of

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For a given reaction, energy of activation for forward reaction E a f is 80 kJ mol -1 and Δ H = - 40 kJ mol -1 . A catalyst lowers E a f to 20 kJ mol − 1 . The ratio of energy of activation for reverse reaction before and after addition of catalyst is:

Quantrex Academy · Accepted Answer

Correct answer: D. 2.0

Δ H = E f - E b - 4 0 = 8 0 - E b E b = 120 kJ/mol, Catalyst lower the E f to 20 kJ/mol for forward reaction then E f ′ = 20 kJ/mol We know catalyst decreases the activation energy equal amount in both direction. E b ′ = 1 2 0 - 6 0 = 60 kJ/mol E b E b ′ = 1 2 0 6 0 = 2

For a given reaction, energy of activation for forward reaction E a f is 80 kJ mol -1 and Δ H = - 40 kJ mol -1 . A catalyst lowers E a f to 20 kJ mol − 1 . The ratio of energy of activation for reverse reaction before and after addition of catalyst is:

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