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For the reaction mechanism of the reaction 2 NO(g) + 2 H 2 (g) → N 2 (g) + 2 H 2 O(g) . Step I 2 NO ⇌ k 1 N 2 O 2 ; K eq fast Step II N 2 O 2 +H 2 → k 2 N 2 O+H 2 O slow Step III N 2 O+H 2 → k 3 N 2 +H 2 O fast Expression of rate of reaction is (Take K eq × k 2 = k')

Options

  1. Ak' [NO] 2 [H 2 ]
  2. Bk' N 2 O 2 [H 2 ]
  3. Ck' N 2 O [H 2 ]
  4. Dk' N 2 O 2

Correct answer

A. k' [NO] 2 [H 2 ]

Step-by-step solution

Step I 2 NO ⇌ k 1 N 2 O 2 ; K eq fast Step II N 2 O 2 + H 2 ⟶ k 2 N 2 O + H 2 O slow Step III N 2 O + H 2 ⟶ k 3 N 2 + H 2 O fast (i) Derive the rate Law Rate = k 2 N 2 O 2 H 2 (Rate determining step) N 2 O 2 NO 2 = K eq ∴ N 2 O 2 = K eq NO 2 Rate = k 2 K eq NO 2 H 2 k' NO 2 H 2 Rate law is third order

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