NTA Abhyas NEET2020ChemistryChemical KineticsPractice
The rate constant k ′ of one reaction is double the rate constant k ″ of another reaction. Then the relationship between the corresponding activation energies of the two reactions E a ′ and E a ′′ will be - (Assume the pre-exponential factor & temperature to be same)
Options
- AE a ′ > E a ′′
- BE a ′ = E a ′′
- CE a ′ < E a ′′
- DE a ′ < 4 E a ′′
Correct answer
C. E a ′ < E a ′′
Step-by-step solution
When activation energy decreases, rate constant increases. As k ′ > k ″ , E a ′ < E a ′′