For the reaction, 2 N 2 O 5 → 4 N O 2 + O 2 the values of rate constant and rate of reaction are respectively 3 × 10 - 5 s - 1 and 2.4 × 10 - 5 m o l L - 1 s - 1 . The concentration of N 2 O 5 i n m o l L - 1 will be:

Step-by-step solution

Since, unit of rate constant is 3.0 × 10 - 5 s - 1 , means order of reaction is one. Thus, our rate law will be: r = k [ N 2 O 5 ] k = 3 × 10 - 5 ∴ N 2 O 5 = r k = 2.4 × 10 - 5 3 × 10 - 5 = 0.8 m o l L - 1