NTA Abhyas NEET2020ChemistryChemical KineticsPractice
For the reaction N 2 O 5 ( g ) → 2 N O 2 ( g ) + 1 / 2 O 2 ( g ) the value of rate of disappearance of N 2 O 5 is given as 6.25 × 1 0 - 3 m o l L - 1 s - 1 . The rate of formation of N O 2 and O 2 is given respectively as
Options
- A1.25 × 1 0 - 2 m o l L - 1 s - 1 and 6.25 × 1 0 - 3 m o l L - 1 s - 1
- B6.25 × 1 0 - 3 m o l L - 1 s - 1 and 6.25 × 1 0 - 3 m o l L - 1 s - 1
- C1.25 × 1 0 - 2 m o l L - 1 s - 1 and 3.125 × 1 0 - 3 m o l L - 1 s - 1
- D6.25 × 1 0 - 3 m o l L - 1 s - 1 and 3.125 × 1 0 - 3 m o l L - 1 s - 1
Correct answer
C. 1.25 × 1 0 - 2 m o l L - 1 s - 1 and 3.125 × 1 0 - 3 m o l L - 1 s - 1
Step-by-step solution
N 2 O 5 → 2 N O 2 + 1 2 O 2 As - d [ N 2 O 5 ] d t = 6.25 × 1 0 - 3 m o l L - 1 s - 1 - d [ N 2 O 5 ] d t = 1 2 d [ N O 2 ] d t = 2 d [ O 2 ] d t d [ N O 2 ] d t = 2 d [ N 2 O 5 ] d t = 2 × 6.25 × 1 0 - 3 = 1.25 × 1 0 - 2 m o l L - 1 s - 1 As 2 d [ O 2 ] d t = d [ N 2 O 5 ] d t d O 2 d t = 6.25 × 1 0 - 3 2 = 3.125 × 1 0 - 3 m o l L - 1 s - 1 = 3.125 × 32 × 1 0 - 3 m o l L - 1 s - 1