NTA Abhyas NEET2020ChemistryChemical KineticsPractice
For the given elementary reaction N 2 + 3 H 2 → 2 N H 3 if Δ [ N H 3 ] Δ t = 2 × 1 0 - 4 m o l L - 1 s - 1 , then calculate value of - Δ [ H 2 ] Δ t
Options
- A1.5 × 1 0 - 4 m o l L - 1 s - 1
- B3 × 1 0 - 4 m o l L - 1 s - 1
- C4 × 1 0 - 4 m o l L - 1 s - 1
- D6.5 × 1 0 - 4 m o l L - 1 s - 1
Correct answer
B. 3 × 1 0 - 4 m o l L - 1 s - 1
Step-by-step solution
N 2 + 3 H 2 ⇌ 2 N H 3 - Δ [ N 2 ] Δ t = - 1 3 Δ [ H 2 ] Δ t = 1 2 Δ [ N H 3 ] Δ t ∴ Δ [ H 2 ] Δ t = 3 2 × Δ [ N H 3 ] Δ t = 3 2 × 2 × 1 0 - 4 = 3 × 10 − 4   molL − 1 s − 1