NTA Abhyas NEET2020ChemistryChemical KineticsPractice
What is the activation energy for a reaction if its rate doubles when temperature is raised from 20°C to 35°C? ( R = 8.314 J m o l - 1 K - 1 )
Options
- A269 k J m o l - 1
- B34.7 k J m o l - 1
- C15.1 k J m o l - 1
- D342 k J m o l - 1
Correct answer
B. 34.7 k J m o l - 1
Step-by-step solution
Using Arrhenius equation l o g 10 k 2 k 1 = E a 2.303 R 1 T 1 - 1 T 2 l o g 10 2 = E a 2.303 × 8.314 × 1 293 - 1 308 On solving E a = 34.67 kJ