What is the two third life of a first order reaction having k = 5.48 × 10 − 14 sec − 1 ?

Step-by-step solution

For two-third of a reaction , A 0   =   a,   A   =   a − 2 3 a   =   a 3 t 2/3   =   2 .303 k   log   A 0 A =   2 .303 k   log   a a 3   =   2 .303 k   log   3 t 2/3   =   2 .303   ×   0 .4771 5 .48   ×   10 − 14   =   2 .01   ×   10 13   s