If the instantaneous rate of appearance of N O 2 g is 0.0400 M / s at some moment in time, what is the rate of disappearance of N 2 O 5 g in M / s ? N 2 O 5 g → 2 N O 2 g + 1 2 O 2 g

Step-by-step solution

N 2 O 5 → 2 N O 2 + 1 2 O 2 r a t e = d ( N 2 O 5 ) d t = 1 2 d ( N O 2 ) d t = 2 d ( O 2 ) d t Rate of disappear of NO 2 = d ( N O 2 ) d t =0.04 d ( N 2 O 5 ) d t = 1 2 d ( N O 2 ) d t = 0.04 2 = 0.02