NTA Abhyas NEET2020ChemistryChemical KineticsPractice
Slope of the straight line obtained by plotting log 10 k against 1 T represents which term?
Options
- A- E a
- B- 2.303 E a ∕ R
- C- E a /( 2.303 R)
- D- E a ∕ R
Correct answer
C. - E a /( 2.303 R)
Step-by-step solution
K = Ae - Ea / (RT) Apply log on both sides: ln k = ln A - E a RT log k = log A - E a 2.303 R × 1 T y = mx + C y = log k , x = 1 T , Slope (m) = - E a 2.303 R