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NTA Abhyas NEET2020ChemistryChemical KineticsPractice

A graph plotted between log t 50 % vs. log concentration is a straight line. What conclusion can you draw from the given graph

Options

  1. An = 1 , t 1 / 2 = 0.693 k
  2. Bn = 2 , t 1 / 2 = 1 a
  3. Cn = 1 , t 1 / 2 = 1 k . a
  4. Dnone of these

Correct answer

A. n = 1 , t 1 / 2 = 0.693 k

Step-by-step solution

t 1 / 2 α a 1 - n or t 1 / 2 = k a 1 - n l o g t 1 / 2 = l o g k + ( 1 - n ) l o g a so slope = 1 - n or 1 - n = 0 or n = 1

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