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In the Haber's process of ammonia manufacture, N 2 ( g ) + 3 H 2 ( g ) → 2 N H 3 ( g ) The rate of appearance of N H 3 is d [ N H 3 ] d t = 2 × 1 0 - 4 m o l L - s e c - 1 The rate of disppearance of N 2 and H 2 will be Rate in terms of H 2 (mol L - 1 s e c - 1 ) Rate in terms of N 2 (mol L - 1 s e c - 1 )

Options

  1. A3 × 1 0 - 4 2 × 1 0 - 4
  2. B3 × 1 0 - 4 1 × 1 0 - 4
  3. C1 × 1 0 - 4 3 × 1 0 - 4
  4. D2 × 1 0 - 4 2 × 1 0 - 4

Correct answer

B. 3 × 1 0 - 4 1 × 1 0 - 4

Step-by-step solution

Rate = + 1 2 d [ N H 3 ] d t = d [ N 2 ] d t = - 1 3 d [ H 2 ] d t - d [ H 2 ] d t = 3 2 × d [ N H 3 ] d t = 3 2 × 2 × 1 0 - 4 = 3 × 1 0 - 4 m o l L - 1 s e c - 1 - d [ N 2 ] d t = 1 2 d [ N H 3 ] d t = 1 2 × 2 × 1 0 - 4 = 1 × 1 0 - 4 m o l L - 1 s e c - 1

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