NTA Abhyas NEET2020ChemistryChemical KineticsPractice
The E a of reaction in the presence of catalyst is 5.25 kJ/mol and in the absence of catalyst is 8.314 kJ m o l - 1 . What is the slope of the plot of lnk vs 1 T in the absence of catalyst. (R = 8 .314 J k − 1 mol − 1 )
Options
- A100
- B-100
- C-1000
- D+1000
Correct answer
C. -1000
Step-by-step solution
ln k = l n A - E a R × 1 T slope = - E a R = - 8.3 × 1 0 3 8.3 = - 1000