NTA Abhyas NEET2020ChemistryChemical KineticsPractice
The rate constant K 1 of a reaction is found to be double that of rate constant K 2 of another reaction. The relationship between corresponding activation energies of the two reactions at same temperature ( E 1 and E 2 ) can be represented as
Options
- AE 1 > E 2
- BE 1 < E 2
- CE 1 = E 2
- DNone of these
Correct answer
D. None of these
Step-by-step solution
K 1 = A 1 e - E 1 / R T and K 2 = A 2 e - E 2 / R T K 1 K 2 = A 1 A 2 e ( - E 1 + E 2 ) / R T As A 1 and A 2 are not given here so none of the relation is correct.