NTA Abhyas NEET2020ChemistryChemical KineticsPractice
A reaction takes place in three steps with activation energy E a 1 = 180 kJ/mol, E a 2 = 80 kJ/mol and E a 3 = 50 kJ/mol respectively. Overall rate constant of the reaction is k = k 1 k 2 k 3 2 / 3 . The activation energy of the reaction will be
Options
- A140 kJ/mol
- B150 kJ/mol
- C43.44 kJ/mol
- D100 kJ/mol
Correct answer
A. 140 kJ/mol
Step-by-step solution
The rate of constant of the reaction is k = k 1 k 2 k 3 2 / 3 Activation energy of the reaction will be E a = 2 3 [ E a 1 + E a 2 - E a 3 ] = 2 3 [ 180 + 80 - 50 ] = 140 kJ/mol.