NTA Abhyas NEET2020ChemistryChemical KineticsPractice
Consider the reaction mechanism A 2 ⇌ K eq 2 A fast (where A is the intermediate) A + B → k 1 P (slow) The rate law for the reaction is
Options
- Ak 1 [ A ] [ B ]
- Bk 1 K 1 / 2 A 2 1 / 2 B
- Ck 1 K 1 / 2 A B
- Dk 1 K 1 / 2 [ A ] 2 [ B ]
Correct answer
B. k 1 K 1 / 2 A 2 1 / 2 B
Step-by-step solution
Over all reaction will be A 2 + 2 B → 2P here 'A' is intermediate A 2 ⇌ K eq 2 A fast K e q = [ A ] 2 / [ A 2 ] [ A ] = K e q [ A 2 ] A + B → k 1 ( s l o w ) → R D S R a t e R D S = k 1 [ A ] [ B ] = k 1 K e q [ A 2 ] . [ B ] Note: Overall reaction is A 2 + 2 B → 2 P .