NTA Abhyas NEET2020ChemistryChemical KineticsPractice
The rate of reaction is expressed as 1 2 + d d t [ C ] = 1 3 - d d t [ D ] = 1 4 + d d t [ A ] = - d d t [ B ] , The reaction is
Options
- A1 4 A + 1 2 C → B + 1 3 D
- B4 A + 2 C → B + 3 D
- CB + 3 D → 4 A + 2 C
- DB + 1 3 D → 1 4 A + 1 2 C
Correct answer
C. B + 3 D → 4 A + 2 C
Step-by-step solution
Rate = 1 2 d [ C ] d t = 1 3 - d [ D ] d t = 1 4 d [ A ] d t = - d [ B ] d t So Stoichiometric coefficient of B = 1 Stoichiometric coefficient of D = 3 Stoichiometric coefficient of A = 4 Stoichiometric coefficient of C = 2 Therefore, the reaction is B + 3D → 4A + 2C.