Question
Which carbon atoms of glucose, numbered from 1 to 6 forms a hemiacetal structure between -CHO and -OH groups.?
MHT CET
Chemistry
Biomolecules
2026
MHT CET 2026 (13 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. C-2
- B. C-3
- C. C-4
- D. C-5
Answer
D. C-5
Step-by-step solution
In the open-chain structure of glucose, the aldehyde group (-CHO) is present at C-1. The cyclic hemiacetal structure is formed by the intramolecular nucleophilic addition of the -OH group at C-5 to the -CHO group at C-1. This results in the formation of a stable six-membered pyranose ring. Thus, the -OH group at C-5 is involved in the hemiacetal formation. Answer: C-5
Related: Chemistry — Biomolecules · All PYQ Banks