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NEET
Exam
NEET
Subject
Physics
Chapter
Units and Dimensions

NEET · Physics · Units and Dimensions

Match the List-I with List-II. The correct match in the following is

Match the List-I with List-II. Match the List-I with List-II. The correct match in the following is
Match the List-I with List-II. The correct match in the following is
The correct match in the following is

Options

  1. AABCD\begin{array}{llll} A & B & C & D \end{array} III  I  II  IV \begin{array}{llll}\text{ III } & \text{ I } & \text{ II } & \text{ IV }\end{array}$
  2. BABCD\begin{array}{llll} A & B & C & D \end{array} III  II  I  IV \begin{array}{llll}\text{ III } & \text{ II } & \text{ I } & \text{ IV }\end{array}$
  3. CABCD\begin{array}{llll} A & B & C & D \end{array} IV  II  I  III\begin{array}{llll}\text{ IV } & \text{ II } & \text{ I } & \text{ III}\end{array}$
  4. DABCD\begin{array}{llll} A & B & C & D \end{array} IV  I  II  III\begin{array}{llll}\text{ IV } & \text{ I } & \text{ II } & \text{ III}\end{array}$

Correct answer

C. ABCD\begin{array}{llll} A & B & C & D \end{array} IV  II  I  III\begin{array}{llll}\text{ IV } & \text{ II } & \text{ I } & \text{ III}\end{array}$

Step-by-step solution

(A) The value of Boltzmann constant =1.38×10−23=1.38 \times 10^{-23} kgm2 s−2k−1\mathrm{kg} \mathrm{m}^2 \mathrm{~s}^{-2} \mathrm{k}^{-1} So dimensions of Boltzmann constant =[ML2 T−2 K−1]=\left[\mathrm{ML}^2 \mathrm{~T}^{-2} \mathrm{~K}^{-1}\right] (B) From stokes' law, F=6πηvr\mathrm{F}=6 \pi \eta v r Coefficient of viscosity η=F6πvr\eta=\frac{\mathrm{F}}{6 \pi v r} Coefficient of viscosity =[ML−1 T−1]=\left[\mathrm{ML}^{-1} \mathrm{~T}^{-1}\right] (C) Water equivalent (W)(\mathrm{W}) is the mass of water which would absorb or evolve the same amount of heat as in done by the body in rising or falling through the same range of temperature. Water equivalent =[ML0 T0]=\left[\mathrm{ML}^0 \mathrm{~T}^0\right] (D) Since Qt=KA(θ1−θ2)l\frac{Q}{t}=\frac{K A\left(\theta_1-\theta_2\right)}{l} ∴\therefore Coefficient of thermal conductivity K=Q.lA(θ1−θ2)t so K=\frac{Q . l}{A\left(\theta_1-\theta_2\right) t} \text{ so } Coefficient of thermal conductivity =[MLT−3 K−1]=\left[\mathrm{MLT}^{-3} \mathrm{~K}^{-1}\right]
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