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NEET
Exam
NEET
Subject
Physics
Chapter
Units and Dimensions

NEET · Physics · Units and Dimensions

Match List I with List II : List-I (Physical Quantity) List-II...

Match List I with List II :

  List-I (Physical Quantity)   List-II (Dimensional Formula)
A Pressure gradient I [M0L2T−2]\left[{M}^{0}{L}^{2}{T}^{- 2}\right]
B Energy density II \left[{M}^{1}{L}^{- 1}{T}^{- 2}\right]</td></tr><tr><td>C</td><td>ElectricField</td><td>III</td><td>[M1L−2T−2]</td> </tr> <tr> <td>C</td> <td>Electric Field</td> <td>III</td> <td>\left[{M}^{1}{L}^{- 2}{T}^{- 2}\right]
D Latent heat IV \left[{M}^{1}{L}^{1}{T}^{- 3}{A}^{- 1}\right]

Choose the correct answer from the options given below:

Options

  1. AA-III, B-II, C-I, D-IV
  2. BA-II, B-III, C-IV, D-I
  3. CA-III, B-II, C-IV, D-I
  4. DA-II, B-III, C-I, D-IV

Correct answer

C. A-III, B-II, C-IV, D-I

Step-by-step solution

(A) Pressure gradient is stated as dPdx=FAl=[MLT−2][L2][L]=[M1L−2T−2]\dfrac{d P}{d x} = \dfrac{F}{Al} = \dfrac{\left[{MLT}^{- 2}\right]}{\left[{L}^{2}\right]\left[L\right]} = \left[{M}^{1}{L}^{- 2}{T}^{- 2}\right]   (III)

(B) Energy density is stated as u=EnergyVolume=[ML2T−2][L3]=[M1L−1T−2]u = \dfrac{Energy}{Volume} = \dfrac{\left[{ML}^{2}{T}^{- 2}\right]}{\left[{L}^{3}\right]} = \left[{M}^{1}{L}^{- 1}{T}^{- 2}\right]   (II)

(C) Electric field is stated as E=ForceCharge=[MLT−2][AT]=[M1L1T−3A−1]E = \dfrac{Force}{Charge} = \dfrac{\left[{MLT}^{- 2}\right]}{\left[AT\right]} = \left[{M}^{1}{L}^{1}{T}^{- 3}{A}^{- 1}\right]   (IV)

(D) Latent heat is stated as L=HeatMass=EnergyMass=[ML2T−2][M]=[M0L2T−2]L = \dfrac{Heat}{Mass} = \dfrac{Energy}{Mass} = \dfrac{\left[{ML}^{2}{T}^{- 2}\right]}{\left[M\right]} = \left[{M}^{0}{L}^{2}{T}^{- 2}\right]     (I)

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