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NEET
Exam
NEET
Subject
Physics
Chapter
Units and Dimensions

NEET · Physics · Units and Dimensions

Match List - I with List - II : List - I List - II (a) h (Planck's...

Match List - I with List - II :

  List - I</td><td> </td><td>List−II</td> <td> </td> <td>List - II
\left(a\right)</td><td></td> <td>h(Planck′sconstant)</td><td>(i)(Planck's constant)</td> <td>\left(i\right) \left[{MLT}^{- 1}\right]</td></tr><tr><td>(b)</td> </tr> <tr> <td>\left(b\right) EE (kinetic energy) \left(ii\right)</td><td>[ML2T−1]</td> <td>\left[{ML}^{2}{T}^{- 1}\right]
\left(c\right)</td><td></td> <td>V(electricpotential)</td><td>(iii)(electric potential)</td> <td>\left(iii\right) \left[{ML}^{2}{T}^{- 2}\right]</td></tr><tr><td>(d)</td> </tr> <tr> <td>\left(d\right) PP (linear momentum) \left(iv\right)</td><td>[ML2I−1T−3]</td> <td>\left[{ML}^{2}{I}^{- 1}{T}^{- 3}\right]

Choose the correct answer from the options given below:

Options

  1. A(a)→(ii),(b)→(iii),(c)→(iv),(d)→(i)\left(a\right) \to \left(ii\right), \left(b\right) \to \left(iii\right), \left(c\right) \to \left(iv\right), \left(d\right) \to \left(i\right)
  2. B(a)→(i),(b)→(ii),(c)→(iv),(d)→(iii)\left(a\right) \to \left(i\right), \left(b\right) \to \left(ii\right), \left(c\right) \to \left(iv\right), \left(d\right) \to \left(iii\right)
  3. C(a)→(iii),(b)→(ii),(c)→(iv),(d)→(i)\left(a\right) \to \left(iii\right), \left(b\right) \to \left(ii\right), \left(c\right) \to \left(iv\right), \left(d\right) \to \left(i\right)
  4. D(a)→(iii),(b)→(iv),(c)→(ii),(d)→(i)\left(a\right) \to \left(iii\right), \left(b\right) \to \left(iv\right), \left(c\right) \to \left(ii\right), \left(d\right) \to \left(i\right)

Correct answer

A. (a)→(ii),(b)→(iii),(c)→(iv),(d)→(i)\left(a\right) \to \left(ii\right), \left(b\right) \to \left(iii\right), \left(c\right) \to \left(iv\right), \left(d\right) \to \left(i\right)

Step-by-step solution

By dimensional analysis.

K.E.=[ML2T−2]K . E . = \left[{ML}^{2}{T}^{- 2}\right]
PP (linear momentum) =[MLT−1]= \left[{MLT}^{- 1}\right]
h(h ( planck's constant )=[ML2T−1]) = \left[{ML}^{2}{T}^{- 1}\right]
VV (electric potential )=[ML2T−3I−1]) = \left[{ML}^{2}{T}^{- 3}{I}^{- 1}\right]

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