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NEET
Exam
NEET
Subject
Physics
Chapter
Units and Dimensions

NEET · Physics · Units and Dimensions

Given below are two statements: one is labelled as Assertion (A)...

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): In the relation x=αβ(1−e−βt)x = \dfrac{\alpha}{\beta} (1 - e^{-\beta t}), where xx is displacement and tt is time, the dimensional formula of α\alpha is [LT−1][L T^{-1}].

Reason (R): The constant β\beta has the dimensional formula of [T][T].

In the light of the above statements, choose the most appropriate answer from the options given below:

Options

  1. ABoth Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  2. BBoth Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
  3. CAssertion (A) is true but Reason (R) is false.
  4. DAssertion (A) is false but Reason (R) is true.

Correct answer

C. Assertion (A) is true but Reason (R) is false.

Step-by-step solution

The exponent of an exponential function must be a dimensionless quantity. Therefore, the term βt\beta t is dimensionless.

[β][t]=[M0L0T0]⇒[β][T]=1⇒[β]=[T−1][\beta][t] = [M^0 L^0 T^0] \Rightarrow [\beta][T] = 1 \Rightarrow [\beta] = [T^{-1}].

Thus, the Reason (R) is false.

According to the principle of homogeneity, the dimensions of the left-hand side must equal the dimensions of the right-hand side. The term (1−e−βt)(1 - e^{-\beta t}) is a dimensionless number.

[x]=[α][β]⇒[L]=[α][T−1]⇒[α]=[L][T−1]=[LT−1][x] = \dfrac{[\alpha]}{[\beta]} \Rightarrow [L] = \dfrac{[\alpha]}{[T^{-1}]} \Rightarrow [\alpha] = [L][T^{-1}] = [L T^{-1}].

Thus, the Assertion (A) is true.

Therefore, Assertion (A) is true but Reason (R) is false.

Answer: Assertion (A) is true but Reason (R) is false.
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