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NEET
Exam
NEET
Subject
Physics
Chapter
Units and Dimensions

NEET · Physics · Units and Dimensions

Match List-I with List-II. List-I List-II (A) Planck's constant /...

Match List-I with List-II.

List-IList-II
(A) Planck's constant / Moment of inertia(I) [M2L−1T0][M^2 L^{-1} T^0]
(B) Pressure / Density(II) [M0L0T−1][M^0 L^0 T^{-1}]
(C) Energy / Gravitational constant(III) [M0L2T−2][M^0 L^2 T^{-2}]
(D) Coefficient of viscosity / Density(IV) [M0L2T−1][M^0 L^2 T^{-1}]

Choose the correct answer from the options given below:

Options

  1. A(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  2. B(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
  3. C(A)-(II), (B)-(III), (C)-(I), (D)-(IV)
  4. D(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Correct answer

C. (A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Step-by-step solution

Let us find the dimensional formula for each ratio in List-I:

(A) Planck's constant (hh) / Moment of inertia (II):
[h]=[ML2T−1][h] = [M L^2 T^{-1}] and [I]=[ML2][I] = [M L^2]
Ratio =[ML2T−1][ML2]=[M0L0T−1]= \dfrac{[M L^2 T^{-1}]}{[M L^2]} = [M^0 L^0 T^{-1}] (Matches with II)

(B) Pressure (PP) / Density (ρ\rho):
[P]=[ML−1T−2][P] = [M L^{-1} T^{-2}] and [ρ]=[ML−3][\rho] = [M L^{-3}]
Ratio =[ML−1T−2][ML−3]=[M0L2T−2]= \dfrac{[M L^{-1} T^{-2}]}{[M L^{-3}]} = [M^0 L^2 T^{-2}] (Matches with III)

(C) Energy (EE) / Gravitational constant (GG):
[E]=[ML2T−2][E] = [M L^2 T^{-2}] and [G]=[M−1L3T−2][G] = [M^{-1} L^3 T^{-2}]
Ratio =[ML2T−2][M−1L3T−2]=[M2L−1T0]= \dfrac{[M L^2 T^{-2}]}{[M^{-1} L^3 T^{-2}]} = [M^2 L^{-1} T^0] (Matches with I)

(D) Coefficient of viscosity (η\eta) / Density (ρ\rho):
[η]=[ML−1T−1][\eta] = [M L^{-1} T^{-1}] and [ρ]=[ML−3][\rho] = [M L^{-3}]
Ratio =[ML−1T−1][ML−3]=[M0L2T−1]= \dfrac{[M L^{-1} T^{-1}]}{[M L^{-3}]} = [M^0 L^2 T^{-1}] (Matches with IV)

Therefore, the correct matching is (A)-(II), (B)-(III), (C)-(I), (D)-(IV).

Answer: (A)-(II), (B)-(III), (C)-(I), (D)-(IV)
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