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NEET
Exam
NEET
Subject
Physics
Chapter
Units and Dimensions

NEET · Physics · Units and Dimensions

The displacement y of a particle in a medium is given by the...

The displacement yy of a particle in a medium is given by the equation y=Asin⁡(bt−cx)y = A \sin(bt - cx), where tt represents time and xx represents distance. The dimensional formula for the ratio bc\dfrac{b}{c} is:

Options

  1. A[M0L−1T][M^0 L^{-1} T]
  2. B[M0L0T0][M^0 L^0 T^0]
  3. C[M0L−1T−1][M^0 L^{-1} T^{-1}]
  4. D[M0LT−1][M^0 L T^{-1}]

Correct answer

D. [M0LT−1][M^0 L T^{-1}]

Step-by-step solution

According to the principle of dimensional homogeneity, the argument of a trigonometric function must be dimensionless.

Therefore, the quantities btandcxbt and cx are dimensionless.

[bt]=[M0L0T0]⇒[b]=1[t]=[T−1][bt] = [M^0 L^0 T^0] \Rightarrow [b] = \dfrac{1}{[t]} = [T^{-1}]

[cx]=[M0L0T0]⇒[c]=1[x]=[L−1][cx] = [M^0 L^0 T^0] \Rightarrow [c] = \dfrac{1}{[x]} = [L^{-1}]

The ratio bc\dfrac{b}{c} has the dimensions:

\left[\dfrac{b}{c}\right] = \dfrac{[T^{-1}]}{[L^{-1}]} = [L T^{-1}]<br><br>Thiscorrespondstothedimensionalformula<br><br>This corresponds to the dimensional formula[M^0 L T^{-1}].<br><br>Answer:.<br><br>Answer:[M^0 L T^{-1}]
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