NEET2010PhysicsUnits and DimensionsActual
The dimension of 1 2 ₀ E ^2 , where ₀ is permittivity of free space and E is electric field, is
Options
- A[ ML ^2 ~T ⁻² ]
- B[ ML ⁻¹ ~T ⁻² ]
- C[ ML ^2 ~T ⁻¹ ]
- D[ MLT ⁻¹ ]
Correct answer
B. [ ML ⁻¹ ~T ⁻² ]
Step-by-step solution
aligned & Dimensions of ₀= [ M ⁻¹ ~L ⁻³ ~T ^4 ~A ^2 ] & Dimensions of E = [ MLT ⁻³ ~A ⁻¹ ] & Dimensions of 1 2 ₀ E ^2= [ M ⁻¹ ~L ⁻³ ~T ^4 ~A ^2 ] & = [ ML ⁻¹ ~T ⁻³ ] [ M ^2 ~L ^2 ~T ⁻⁶ ~A ⁻² ] aligned