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NEET 2004
Exam
NEET
Year
2004
Subject
Physics
Chapter
Units and Dimensions

NEET 2004 · Physics · Units and Dimensions

The unit of permittivity of free space _0 , is:

The unit of permittivity of free space ε0\varepsilon_0, is:

Options

  1. Acoulomb/newton-metre
  2. Bnewton-metre 2/{ }^2 / coulomb 2^2
  3. Ccoulomb 2/{ }^2 / newton-metre 2^2
  4. Dcoulomb 2/^2 / (newton-metre) 2{ }^2

Correct answer

C. coulomb 2/{ }^2 / newton-metre 2^2

Step-by-step solution

We know thatF=14πε0q2r2⇒ε0=14πa2Frr2=C2 N−m2\begin{aligned}& F=\frac{1}{4 \pi \varepsilon_0} \frac{q^2}{r^2}\\ & \Rightarrow \quad \varepsilon_0=\frac{1}{4 \pi} \frac{a^2}{\mathrm{Fr} r^2}=\frac{\mathrm{C}^2}{\mathrm{~N}-\mathrm{m}^2}\\ & \end{aligned}
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