NEET2004PhysicsUnits and DimensionsActual
Using mass (M) , length (L) , time (T) and current (A) as fundamental quantities, the dimension of permittivity is
Options
- A[ ML ⁻² ~T ^2 ~A ]
- B[ M ⁻¹ ~L ⁻³ ~T ^4 ~A ^2 ]
- C[ MLT ⁻² ~A ]
- D[ ML ^2 ~T ⁻¹ ~A ^2 ] .
Correct answer
B. [ M ⁻¹ ~L ⁻³ ~T ^4 ~A ^2 ]
Step-by-step solution
Force of attraction between two charges is given by aligned F & = 1 4 ₀ q₁ q₂ r^2 ₀ & = 1 4 1 F q₁ q₂ r^2 = A ^2 ~T ^2 MLT ⁻² ~L ^2 & = [ M ⁻¹ ~L ⁻³ ~T ^4 ~A ^2 ] . aligned (where 4 is dimensionless) = [ M ⁻¹ ~L ⁻³ ~T ^4 ~A ^2 ]